document.write( "Question 348362: How do you set up the problem of \"Find the dimensions of a rectangle whose width is 6 less than the legth\" The perimeter is 56 \n" ); document.write( "

Algebra.Com's Answer #249042 by Deja12347(3) $\"\"$ $\"About$

You can put this solution on YOUR website!
56= 2(w-6)+2w (Yes you use 2 w's. You subsitute l or length for another w.
\n" ); document.write( "56= 2w-12+2w (distributive property
\n" ); document.write( "56= 4w-12 ( combine like terms)
\n" ); document.write( "68=4w (add by 12 or do the opposite then divide by 4)
\n" ); document.write( "17=w \n" ); document.write( "

\n" );