document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=348179>Question 348179</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solving a quadratic equation with the Indian method:\r<BR>\n" );
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document.write( "Solve x^2+3x-10=0\r<BR>\n" );
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document.write( "x^2+3x=10\r<BR>\n" );
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document.write( "Next step is to multiply each term by four times the original coefficient of the x^2 term\r<BR>\n" );
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document.write( "4x^2+12x=40\r<BR>\n" );
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document.write( "Next square the original coefficient of x and add it to both sides of the equation:\r<BR>\n" );
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document.write( "4x^2+12x+9=40+9\r<BR>\n" );
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document.write( "4x^2+12x+9=49\r<BR>\n" );
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document.write( "Next is to take the square root of both sides, this is where I'm confused by my textbook:\r<BR>\n" );
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document.write( "I know that the square root of 4x^2 = 2x but the square root of 12x is not going to be a 'clean' number and the square root of 9 and 49 are 3 and 7... the textbook says that 4x^2+12x+9=49  taken to the square root is\r<BR>\n" );
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document.write( "2x  +   3=  +-7\r<BR>\n" );
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document.write( "Where did the 12x go? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248958 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248958\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve x^2+3x-10=0 <BR>\n" );
document.write( "x^2+3x=10 <BR>\n" );
document.write( "Next step is to multiply each term by four times the original coefficient of the x^2 term <BR>\n" );
document.write( "4x^2+12x=40 <BR>\n" );
document.write( "Next square the original coefficient of x and add it to both sides of the equation: <BR>\n" );
document.write( "4x^2+12x+9=40+9 <BR>\n" );
document.write( "4x^2+12x+9=49 <BR>\n" );
document.write( "Next is to take the square root of both sides<BR>\n" );
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document.write( "The left side factors as (2x+3)^2<BR>\n" );
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document.write( "(2x+3)^2 = 49<BR>\n" );
document.write( "Taking the square root of both sides you get:<BR>\n" );
document.write( "2x+3 = 7 or 2x+3 = -7<BR>\n" );
document.write( "2x = 4 or 2x = -10<BR>\n" );
document.write( "x = 2 or x = -5<BR>\n" );
document.write( "====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "==================== </SPAN>\n" );
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