document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=348130>Question 348130</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 3 less than twice the width the perimeter of the rectangle is 78 find the dimensions of the rectangle   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248935 by </B><A HREF=/tutors/aboutme.mpl?userid=london+maths+tutor><B>london maths tutor(243)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=london+maths+tutor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=london+maths+tutor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248935\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the length be L and width be W and Perimeter be P \r<BR>\n" );
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document.write( "L = 2W-3 \r<BR>\n" );
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document.write( "P = 78 \r<BR>\n" );
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document.write( "By theory, P = 2L + 2W\r<BR>\n" );
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document.write( "Therefore,\r<BR>\n" );
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document.write( "78 = 2(2W-3) + 2W<BR>\n" );
document.write( "78 = 4W - 6 + 2W<BR>\n" );
document.write( "78 = 6W - 6 <BR>\n" );
document.write( "78 + 6 = 6W<BR>\n" );
document.write( "84 = 6W<BR>\n" );
document.write( "W = 84/6<BR>\n" );
document.write( "W = 14 \r<BR>\n" );
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document.write( "Therefore: L = 2(14)-3 = 25 \r<BR>\n" );
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document.write( "Answer : Length = 25 and Width = 14\r<BR>\n" );
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document.write( "Hope this is helpful :)<BR>\n" );
document.write( "For more solutions, visit http://www.london-maths-tutor.co.uk/ </SPAN>\n" );
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