document.write( "Question 348130: the length of a rectangle is 3 less than twice the width the perimeter of the rectangle is 78 find the dimensions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #248928 by ovie27(16)\"\" \"About 
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\n" ); document.write( "Let:\r
\n" ); document.write( "\n" ); document.write( "x = length of the rectangle
\n" ); document.write( "y = width of the rectangle\r
\n" ); document.write( "\n" ); document.write( "x = 2y -3\r
\n" ); document.write( "\n" ); document.write( "perimeter = 2x + 2y = 78\r
\n" ); document.write( "\n" ); document.write( "Plug in x into the above equation:\r
\n" ); document.write( "\n" ); document.write( "2(2y-3) + 2y = 78
\n" ); document.write( "4y - 6 + 2y = 78
\n" ); document.write( "6y - 6 = 78\r
\n" ); document.write( "\n" ); document.write( "bring the 6 to the other side:\r
\n" ); document.write( "\n" ); document.write( "6y = 84\r
\n" ); document.write( "\n" ); document.write( "divide both sides by 6:\r
\n" ); document.write( "\n" ); document.write( "y = 14 = the width of the rectangle\r
\n" ); document.write( "\n" ); document.write( "The length is 2(14)-3 = 25\r
\n" ); document.write( "\n" ); document.write( "So, the length of the rectangle is 25 units, and the width is 14 units.
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