document.write( "Question 348096: Tracy, Stacy and Fred assembled a very large puzzle together in 40 hours. If Stacy worked twice as fast as Fred and Tracy worked just as fast as Stacy, how long would it have taken Fred to assemble the puzzle alone? \n" ); document.write( "

Algebra.Com's Answer #248924 by stanbon(75887) $\"\"$ $\"About$

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Tracy, Stacy and Fred assembled a very large puzzle together in 40 hours. If Stacy worked twice as fast as Fred and Tracy worked just as fast as Stacy, how long would it have taken Fred to assemble the puzzle alone?
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\n" ); document.write( "Together rate: 1/40 job/hr
\n" ); document.write( "---
\n" ); document.write( "Fred rate = 1/2x job/hr
\n" ); document.write( "---
\n" ); document.write( "Stacy rate = 1/x job/hr
\n" ); document.write( "---
\n" ); document.write( "Tracy rate = 1/x job/hr
\n" ); document.write( "---------------------------
\n" ); document.write( "Equation:
\n" ); document.write( "1/x + 1/x + 1/2x = 1/40
\n" ); document.write( "---
\n" ); document.write( "40 + 40 + 20 = x
\n" ); document.write( "x = 100 hrs
\n" ); document.write( "---
\n" ); document.write( "Fred's time alone = 2x = 200 hrs.
\n" ); document.write( "====================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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