document.write( "Question 348105: \"+5%2Fy-3+=+y%2B7+%2F+2y-6+%2B+1+\" \n" ); document.write( "
Algebra.Com's Answer #248921 by stanbon(75887)\"\" \"About 
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5/(y-3) = (y+7)/(2y-6) + 1
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\n" ); document.write( "Multiply thru by 2y-6 to get:
\n" ); document.write( "10 = y+7 + 2y-6
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\n" ); document.write( "3y+1 = 10
\n" ); document.write( "3y = 9
\n" ); document.write( "y = 3
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\n" ); document.write( "But 3 cannot be a solution because y-3
\n" ); document.write( "is a denominator.
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\n" ); document.write( "Ans: No solution
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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