document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=346762>Question 346762</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if two angles are complementary and one angle measures 4x + 3 and the other measures 2x + 21, find the measure of an angle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248897 by </B><A HREF=/tutors/aboutme.mpl?userid=Chandni><B>Chandni(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Chandni><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248897\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Complementary means=90<BR>\n" );
document.write( "Let angle A=4x+3<BR>\n" );
document.write( "Let angle B=2x+21<BR>\n" );
document.write( "From A+B=90<BR>\n" );
document.write( "Substitute the values<BR>\n" );
document.write( "(4x+3)+ (2x+21)=90<BR>\n" );
document.write( "Collect like terms<BR>\n" );
document.write( "4x+2x+3+21=90<BR>\n" );
document.write( "6x+24=90<BR>\n" );
document.write( "6x=90-24<BR>\n" );
document.write( "6x=66<BR>\n" );
document.write( "x=66/6<BR>\n" );
document.write( "x=11<BR>\n" );
document.write( "If x=11, 4(11)+3=44+3=47<BR>\n" );
document.write( "         2(11)+21=22+21=43<BR>\n" );
document.write( "Check:A+B=90<BR>\n" );
document.write( "      47+43=90<BR>\n" );
document.write( "Therefore; the measure of the angles are 47 and 43 respectively. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );