document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=348076>Question 348076</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much water should be added to 1 gallon of antifreeze to obtain a solution that is 60% antifreeze? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248892 by </B><A HREF=/tutors/aboutme.mpl?userid=Jk22><B>Jk22(389)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Jk22><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Jk22><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248892\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1 gallon should equal 60%. Let w water gallon added : the total is 1+w gallon, of which 60% is antefreeze, hence 1 gallon : <BR>\n" );
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document.write( "0.6*(1+w)=1=0.6+0.6w<BR>\n" );
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document.write( "0.4=0.6w<BR>\n" );
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document.write( "w=4/6=2/3~0.66 gallons.<BR>\n" );
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document.write( "Verif : Total : 1+2/3, % antifreeze : 1/(1+2/3)=3/(3+2)=3/5=60/100. </SPAN>\n" );
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