document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=348041>Question 348041</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 7 inches less than 3 times its width. if the perimeter of the rectangle is 50 inches, what are its dimensions? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248875 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248875\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> width =x<BR>\n" );
document.write( "length = 3x-7<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Perimeter = 50<BR>\n" );
document.write( "...<BR>\n" );
document.write( "Perimeter = 2*(L+W)<BR>\n" );
document.write( "2*(x+3x-7)=50<BR>\n" );
document.write( "8x-14=50<BR>\n" );
document.write( "8x=50+14<BR>\n" );
document.write( "8x=64<BR>\n" );
document.write( "x= 8 the width<BR>\n" );
document.write( "Length = 3x-7 = 3*8-7<BR>\n" );
document.write( "=24-7<BR>\n" );
document.write( "=17 length </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );