document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=348023>Question 348023</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello! I'm just having some trouble with a question on an assignment I have due Monday. \r<BR>\n" );
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document.write( "Question: Charlie is 5 years old. He is a very picky eater and can count to 5. His dad makes him a giant bowl of grapes containing only good grapes with the same proportion of red, green, and black grapes. (0.22 Green grapes, 0.24 Black grapes, and 0.54 red grapes. I calculated this in the previous problem.) Charlie randomly picks out 5 grapes from the bowl with replacement after each grape. Charlie will eat one of the grapes that has the majority in 5. If there is a tie, Charlie will not eat a grape in that round. Charlie's dad replaces the grape that has been eaten after each round.\r<BR>\n" );
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document.write( "a) Let g be the event of Charlie eating a green grape. Determine the theoretical probability of event g, P(g)\r<BR>\n" );
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document.write( "Any help would be appreciated. Thank you so much! :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248871 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248871\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> this is a binomial problem\r<BR>\n" );
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document.write( "a picked out grape is green (p(G) = .22) or not green (p(N) = .78)\r<BR>\n" );
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document.write( "Charlie must pick out 3 or more green grapes to eat one\r<BR>\n" );
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document.write( "you need to sum the first 3 terms of the expansion (p(G) + p(N))^5\r<BR>\n" );
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document.write( "5C5{[p(G)]^5} + 5C4{[p(G)]^4}[p(N)] + 5C3{[p(G)]^3}{[p(N)]^2} </SPAN>\n" );
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