document.write( "Question 39427This question is from textbook Technical mathematics
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document.write( ": Working together, two pipes, A and B, can fill a tank in 4h. It takes pipe A 6h longer than pipe B to fill the tank alone. How long would it take each pipe alone to fill the tank? \n" );
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Algebra.Com's Answer #24887 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Working together, two pipes, A and B, can fill a tank in 4h. It takes pipe A 6h longer than pipe B to fill the tank alone. How long would it take each pipe alone to fill the tank?\r \n" ); document.write( "\n" ); document.write( "Pipe B Data: \n" ); document.write( "Time to fill=x hrs; Rate=(1/x) job/hr \n" ); document.write( "Pipe A Data: \n" ); document.write( "Time to fill=x+6 hrs; Rate=(1/(x+6)) job/hr \n" ); document.write( "Together Data: \n" ); document.write( "Time to fill=4 hrs; Rate=(1/4) job/hr\r \n" ); document.write( "\n" ); document.write( "EQUATION: \n" ); document.write( "1/x + 1/(x+6) = 1/4 \n" ); document.write( "Multiply thru by 4x(x+6) to get: \n" ); document.write( "4(x+6)+4x=x(x+6) \n" ); document.write( "4x+24+4x=x^2+6x \n" ); document.write( "x^2-2x-24=0 \n" ); document.write( "(x-6)(x+4)=0 \n" ); document.write( "x=6 hrs. (time to fill for pipe B) \n" ); document.write( "x+6=12 hrs (time to fill for pipe A) \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |