document.write( "Question 39434: In a parallel circuit, the joint resistance is 8 ohms. If one resistor is 12 ohms less than the second resistor, find both resistors. \n" ); document.write( "
Algebra.Com's Answer #24885 by longjonsilver(2297)\"\" \"About 
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parallel circuit with resistors A and B, then the total resistance is given by R where \r
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\n" ); document.write( "\n" ); document.write( "\"+1%2FR+=+1%2FA+%2B+1%2FB+\"
\n" ); document.write( "\"+1%2FR+=+B%2F%28AB%29+%2B+A%2F%28AB%29+\"
\n" ); document.write( "\"+1%2FR+=+%28A%2BB%29%2F%28AB%29+\"
\n" ); document.write( "\"+R+=+%28AB%29%2F%28A%2BB%29+\"\r
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\n" ); document.write( "\n" ); document.write( "so, given our info of one resistor being x and the other being (x-12), we get:\r
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\n" ); document.write( "\n" ); document.write( "\"+8+=+%28x%28x-12%29%29%2F%28x%2B%28x-12%29%29+\"
\n" ); document.write( "\"+8+=+%28x%5E2-12x%29%2F%282x-12%29+\"
\n" ); document.write( "\"+8%282x-12%29+=+x%5E2-12x+\"
\n" ); document.write( "\"+16x-96+=+x%5E2-12x+\"
\n" ); document.write( "\"+0+=+x%5E2-28x%2B96+\"
\n" ); document.write( "\"+x%5E2-28x%2B96+=+0+\"
\n" ); document.write( "(x-4)(x-24) = 0
\n" ); document.write( "so x-4=0 or x-24=0
\n" ); document.write( "x=4 or x=24\r
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\n" ); document.write( "\n" ); document.write( "Now x is not 4 for our resistor problem, since the other resistor would then be 4-12 --> -8. This is physically impossible.\r
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\n" ); document.write( "\n" ); document.write( "So, the only answer we have is that the resistors are 24 and (24-12) --> 12.\r
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\n" ); document.write( "\n" ); document.write( "jon.
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