document.write( "Question 347799: latoya is twice as old as her cousin was 3 years ago. if the sum of their ages now is 15, how old is each one of them? \n" ); document.write( "
Algebra.Com's Answer #248843 by ankor@dixie-net.com(22740)\"\" \"About 
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latoya is twice as old as her cousin was 3 years ago. if the sum of their ages now is 15, how old is each one of them?
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\n" ); document.write( "Let t = L's present
\n" ); document.write( "Let c = cousin's present age
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\n" ); document.write( "Write an equation for each statement
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\n" ); document.write( "\"latoya is twice as old as her cousin was 3 years ago.\"
\n" ); document.write( "t = 2(c-3)
\n" ); document.write( "t = 2c - 6
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\n" ); document.write( "\"the sum of their ages now is 15,\"
\n" ); document.write( "t + c = 15
\n" ); document.write( "Replace t with (2c-6)
\n" ); document.write( "2c - 6 + c = 15
\n" ); document.write( "3c = 15 + 6
\n" ); document.write( "3c = 21
\n" ); document.write( "c = \"21%2F3\"
\n" ); document.write( "c = 7 yrs, cousin's present age
\n" ); document.write( "then
\n" ); document.write( "t = 2c - 6
\n" ); document.write( "t = 2(7) - 6
\n" ); document.write( "t = 8 yrs is L's present age
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