document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39408>Question 39408</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 100.  One number is 5 less than twice the other.  Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24884 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24884\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the two numbers be x and y.<BR>\n" );
document.write( "Thus<BR>\n" );
document.write( "x + y = 100<BR>\n" );
document.write( "and<BR>\n" );
document.write( "x = 2y - 5<BR>\n" );
document.write( "Now substitute for x in the first equation and get<BR>\n" );
document.write( "2y - 5 + y = 100<BR>\n" );
document.write( "3y - 5 = 100<BR>\n" );
document.write( "3y = 105<BR>\n" );
document.write( "y = 35 and since they add to 100,<BR>\n" );
document.write( "x = 65 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );