document.write( "Question 348019: The perimeter of a rectangle equals one and a half times its area. Express the length of the rectangle in terms of the width (use variable \"w\" for width). \n" ); document.write( "
Algebra.Com's Answer #248839 by nerdybill(7384)\"\" \"About 
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The perimeter of a rectangle equals one and a half times its area. Express the length of the rectangle in terms of the width (use variable \"w\" for width)
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\n" ); document.write( "Area of any rectangle = width * length
\n" ); document.write( "Perimeter of any rectangle = 2(width+length)
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\n" ); document.write( "Let w = width
\n" ); document.write( "and temporarily
\n" ); document.write( "x = length
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\n" ); document.write( "From the problem, perimeter is:
\n" ); document.write( "1.5wx
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\n" ); document.write( "But,
\n" ); document.write( "Perimeter = 2(w+x)
\n" ); document.write( "So, then we have
\n" ); document.write( "1.5wx = 2(w+x)
\n" ); document.write( "Solving for x:
\n" ); document.write( "1.5wx = 2(w+x)
\n" ); document.write( "1.5wx = 2w+2x
\n" ); document.write( "1.5wx-2x = 2w
\n" ); document.write( "factoring the left:
\n" ); document.write( "x(1.5w-2) = 2w
\n" ); document.write( "x = 2w/(1.5w-2)
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\n" ); document.write( "So, your answer would be
\n" ); document.write( "length is equal to:
\n" ); document.write( "2w/(1.5w-2) \n" ); document.write( "
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