document.write( "Question 347821: A rectangular plot of ground having dimensions 25 feet by 38 feet is surrounded by a walk of uniform width. If the area of the walk is 568 ft 2 , what is its width? \r
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Algebra.Com's Answer #248834 by ankor@dixie-net.com(22740)\"\" \"About 
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A rectangular plot of ground having dimensions 25 feet by 38 feet is surrounded by a walk of uniform width.
\n" ); document.write( "If the area of the walk is 568 ft 2, what is its width?
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\n" ); document.write( "Find the area of the plot of ground 25 * 38 = 950 sq/ft
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\n" ); document.write( "Let w = the width of the walk
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\n" ); document.write( "the overall dimensions will be: 2w+25 by 2w+38
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\n" ); document.write( "(2w+25)*(2w+38) = total area of plot and walkway
\n" ); document.write( "FOILs to 4w^2 + 76w + 50w + 980 = 4w^2 + 126w + 980
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\n" ); document.write( "overall area - plot area = walkway area
\n" ); document.write( "4w^2 + 126w + 950 - 950 = 568
\n" ); document.write( "4w^2 + 126w - 568 = 0
\n" ); document.write( "simplify, divide by 2
\n" ); document.write( "2w^2 + 63w - 284 = 0
\n" ); document.write( "You can use the quadratic formula, but this will factor
\n" ); document.write( "(2W + 71)(w - 4) = 0
\n" ); document.write( "the positive solution
\n" ); document.write( "w = 4 ft is the width of the walkway
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\n" ); document.write( "See if that is true
\n" ); document.write( "Overall area: (8+25)*(8+38) = 1518
\n" ); document.write( "1518 - 950 = 568
\n" ); document.write( "Plot area: 980
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