document.write( "Question 347821: A rectangular plot of ground having dimensions 25 feet by 38 feet is surrounded by a walk of uniform width. If the area of the walk is 568 ft 2 , what is its width? \r
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Algebra.Com's Answer #248834 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A rectangular plot of ground having dimensions 25 feet by 38 feet is surrounded by a walk of uniform width. \n" ); document.write( "If the area of the walk is 568 ft 2, what is its width? \n" ); document.write( ": \n" ); document.write( "Find the area of the plot of ground 25 * 38 = 950 sq/ft \n" ); document.write( "; \n" ); document.write( "Let w = the width of the walk \n" ); document.write( "then \n" ); document.write( "the overall dimensions will be: 2w+25 by 2w+38 \n" ); document.write( "then \n" ); document.write( "(2w+25)*(2w+38) = total area of plot and walkway \n" ); document.write( "FOILs to 4w^2 + 76w + 50w + 980 = 4w^2 + 126w + 980 \n" ); document.write( ": \n" ); document.write( "overall area - plot area = walkway area \n" ); document.write( "4w^2 + 126w + 950 - 950 = 568 \n" ); document.write( "4w^2 + 126w - 568 = 0 \n" ); document.write( "simplify, divide by 2 \n" ); document.write( "2w^2 + 63w - 284 = 0 \n" ); document.write( "You can use the quadratic formula, but this will factor \n" ); document.write( "(2W + 71)(w - 4) = 0 \n" ); document.write( "the positive solution \n" ); document.write( "w = 4 ft is the width of the walkway \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if that is true \n" ); document.write( "Overall area: (8+25)*(8+38) = 1518 \n" ); document.write( "1518 - 950 = 568 \n" ); document.write( "Plot area: 980 \n" ); document.write( " |