document.write( "Question 348013: Find two positive numbers so that twice their sum equals their product and one number is 6 times the other number \n" ); document.write( "
Algebra.Com's Answer #248830 by ovie27(16)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "1st number = x
\n" ); document.write( "2nd number = y\r
\n" ); document.write( "\n" ); document.write( "2(x+y)=xy\r
\n" ); document.write( "\n" ); document.write( "x=6y\r
\n" ); document.write( "\n" ); document.write( "plug in the x into the above equation:\r
\n" ); document.write( "\n" ); document.write( "2(6y+y)=6y(y)
\n" ); document.write( "12y+2y = 6(y^2)
\n" ); document.write( "14y=6(y^2)
\n" ); document.write( "divide both sides by y:\r
\n" ); document.write( "\n" ); document.write( "14=6y\r
\n" ); document.write( "\n" ); document.write( "so, y = 14/6 which is 7/3.\r
\n" ); document.write( "\n" ); document.write( "Now, we can find x:\r
\n" ); document.write( "\n" ); document.write( "x = 6(7/3) which is 42/3 which is 14. \r
\n" ); document.write( "\n" ); document.write( "So, the two positive numbers are 7/3 and 14.
\n" ); document.write( "
\n" );