document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=5001>Question 5001</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a motorboat traveled for 2 hours with an 8 km/h current. the return trip against the same current took 3 hours. find the speed of the motorboat in still water. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2488 by </B><A HREF=/tutors/aboutme.mpl?userid=xcentaur><B>xcentaur(357)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=xcentaur><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2488\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the speed of the motorboat be x kmph<BR>\n" );
document.write( "the speed of the current be y kmph = 8 kmph<BR>\n" );
document.write( "<P><BR>\n" );
document.write( "now,journey with the current:<BR>\n" );
document.write( "speed=x+y=(x+8)kmph,time=2 hours<BR>\n" );
document.write( "d=2(x+8)=(2x+16)km<BR>\n" );
document.write( "<P><BR>\n" );
document.write( "now considering return journey:<BR>\n" );
document.write( "speed=x-y=(x-8)kmph,time=3 hours<BR>\n" );
document.write( "distance=3(x-8)=(3x-24)km<BR>\n" );
document.write( "<P><BR>\n" );
document.write( "but the distance in both cases must be the same,<BR>\n" );
document.write( "hence 2x+16=3x-24<BR>\n" );
document.write( "16+24=3x-2x<BR>\n" );
document.write( "x=40 kmph<BR>\n" );
document.write( "<P><BR>\n" );
document.write( "<B>Thus speed of the motorboat in still water=40kmph</b><BR>\n" );
document.write( "<P><BR>\n" );
document.write( "Hope this helps,<BR>\n" );
document.write( "good luck.\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );