document.write( "Question 347944: In a class of 30 students, there are six more boys than girls. What percentage of this class are girls? \n" ); document.write( "

Algebra.Com's Answer #248798 by ovie27(16) $\"\"$ $\"About$

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Suppose,\r
\n" ); document.write( "\n" ); document.write( "x = number of girls
\n" ); document.write( "y = number of boys\r
\n" ); document.write( "\n" ); document.write( "so, x + y = 30 \r
\n" ); document.write( "\n" ); document.write( "There are six more boys than girls, so:\r
\n" ); document.write( "\n" ); document.write( "y = x + 6\r
\n" ); document.write( "\n" ); document.write( "Plug in y into the equation:\r
\n" ); document.write( "\n" ); document.write( "x + (x + 6) = 30
\n" ); document.write( "2x +6 = 30
\n" ); document.write( "2x = 24
\n" ); document.write( "x = 12\r
\n" ); document.write( "\n" ); document.write( "So, there are 12 girls in the class, and there are 18 boys in the class.\r
\n" ); document.write( "\n" ); document.write( "Now the percentage: ( let z equal the unknown percentage)\r
\n" ); document.write( "\n" ); document.write( "12/30 = z/100\r
\n" ); document.write( "\n" ); document.write( "cross multiply:\r
\n" ); document.write( "\n" ); document.write( "1200 = 30z
\n" ); document.write( "z = 40 %\r
\n" ); document.write( "\n" ); document.write( "So, the percentage of girls in the class is 40 percent. \n" ); document.write( "

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