document.write( "Question 347947: use summation notation to write the series: 1- 1/2+ 1/4- 1/8+ ...- 1/128 \n" ); document.write( "
Algebra.Com's Answer #248763 by ewatrrr(24785)\"\" \"About 
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note \"a%5Bn%5D=a%5B1%5D%2Ar%5E%28n-1%29\"where \"a%5B1%5D\" is the first term and n the common ratio. In this series the common ratio is r = -(1/2)
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\n" ); document.write( "knowing the value of the nth term: find the number of terms in the series
\n" ); document.write( "\"%28-1%2F128%29=+%28-1%2F2%29%5B1%5D%2Ar%5E%28n-1%29\"
\n" ); document.write( "\"%28-1%2F128%29=+%28-1%2F2%29%2Ar%5E%28n-1%29\"
\n" ); document.write( "\"%281%2F64%29=+%28-1%2F2%29%5E%28n-1%29\"
\n" ); document.write( "\"%28-1%2F2%29%5E6=+%28-1%2F2%29%5E%28n-1%29\"
\n" ); document.write( "6 = n-1
\n" ); document.write( "7 =n
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\n" ); document.write( "finding the sum of the terms can be found by the following
\n" ); document.write( "\"S%5Bn%5D+=+a%5B1%5D%281-r%5En%29%2F%281-r%29\"
\n" ); document.write( "substitute:\r
\n" ); document.write( "\n" ); document.write( "\"sum%28%282%2F3%29%281-r%5En%29%2C+n=1%2C+7+%29\"
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