document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=347931>Question 347931</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A father is 10 years older than three times his son's age.<BR>\n" );
document.write( "The sum of their ages is 58. What is the difference between the father's age and his son's?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248752 by </B><A HREF=/tutors/aboutme.mpl?userid=hellen><B>hellen(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hellen><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248752\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Son's age is x.<BR>\n" );
document.write( "Dad's age would be 3x+10 because he is 10 years older than 3 times the son's age.<BR>\n" );
document.write( "The total age is 58.\r<BR>\n" );
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document.write( "Therefore:  x+3x+10=58<BR>\n" );
document.write( "              4x+10=58  (add x+3x)<BR>\n" );
document.write( "                4x=48    (subtract 10 from each side)<BR>\n" );
document.write( "                  x=12   (divide each side by 4)\r<BR>\n" );
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document.write( "Therefore the son is 12 years old.  The dad is 46 years old.  The difference in their ages is 34. </SPAN>\n" );
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