document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39443>Question 39443</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve -4e^2x + 3 = -5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24875 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24875\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From -4e^2x + 3 = -5<BR>\n" );
document.write( "subtract three, then divide by minus four...<BR>\n" );
document.write( "-4e^2x = -8<BR>\n" );
document.write( "e^2x = 2<BR>\n" );
document.write( "take ln<BR>\n" );
document.write( "2x = ln 2<BR>\n" );
document.write( "x = (1/2)*ln 2 </SPAN>\n" );
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