document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=347855>Question 347855</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The problem says for me to solve but I don't even know how to begin. I know I need an LCM but what is it, 3x? Then what, do I divide both sides by the 3x? WHen I did that I came up with 6 = 21 + x<BR>\n" );
document.write( "solve for x: 6-21=x<BR>\n" );
document.write( "              -15=x<BR>\n" );
document.write( "Is this right?\r<BR>\n" );
document.write( "\n" );
document.write( "2/x = 7/x - 1/3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248713 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248713\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2/x = 7/x - 1/3<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Multiply both sides by 3x to get rid of the denominators.<BR>\n" );
document.write( "6 = 21 - x<BR>\n" );
document.write( "x = 21-6<BR>\n" );
document.write( "x = 15<BR>\n" );
document.write( "=================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );