document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=347845>Question 347845</A>: <I><SPAN STYLE=\"word-break: break-all;\"> five yrs ago lucy was three times as old as lovely. 10 yrs later, lucy would be twice as old as lovely how old are they now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248693 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248693\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5 years ago lovely = x years<BR>\n" );
document.write( "Lucy = 3x<BR>\n" );
document.write( "...<BR>\n" );
document.write( "After 10 years<BR>\n" );
document.write( "lovely x+15<BR>\n" );
document.write( "lucy = 3x+15<BR>\n" );
document.write( "..<BR>\n" );
document.write( "3x+15=2(x+15)<BR>\n" );
document.write( "3x+15=2x+30<BR>\n" );
document.write( "3x-2x=30-15<BR>\n" );
document.write( "x=15<BR>\n" );
document.write( "lovely is 15+5 = 20 years<BR>\n" );
document.write( "Lucy = 65 years </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );