document.write( "Question 39411: Mr. Granger is 10 years more than twice as old as his son. However, last year he was 4 years less than 3 times as old as his son. How old are Mr. Granger and his son? \n" ); document.write( "
Algebra.Com's Answer #24866 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! Let x be the son's age NOW (always set up variables in the NOW). \n" ); document.write( "Then Granger's age NOW is 10 + 2x. \n" ); document.write( "Last year, he was 9 + 2x. The son was x - 1. So \n" ); document.write( "(9 + 2x) + 4 = 3(x - 1) \n" ); document.write( "2x + 13 = 3x - 3 \n" ); document.write( "x = 16 \n" ); document.write( "Granger = 10 + 2x = 10 + 32 = 42 \n" ); document.write( " |