document.write( "Question 347782: An airplane takes 3 hours to travel a distance of 2160 miles with the wind. The return trip takes 4 hours against the wind. Find the speed of the plane in still air and the speed of the wind.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #248651 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
time = distance /speed
\n" ); document.write( "speed upwind = x-y
\n" ); document.write( "speed downwind = x+y
\n" ); document.write( "time = 2160/x+y=3
\n" ); document.write( "x+y = 2160/3
\n" ); document.write( "x+y=720........................1
\n" ); document.write( "upwind
\n" ); document.write( "time = 2160/x-y = 4
\n" ); document.write( "2160/4 = x-y
\n" ); document.write( "340 = x-y......................2
\n" ); document.write( "add equation 1 & 2
\n" ); document.write( "2x= 1060
\n" ); document.write( "x= 530 mph
\n" ); document.write( ".....
\n" ); document.write( "x+y=720
\n" ); document.write( "530+y=720
\n" ); document.write( "y=720-530
\n" ); document.write( "y= 90 mph
\n" ); document.write( "
\n" ); document.write( "
\n" );