document.write( "Question 347782: An airplane takes 3 hours to travel a distance of 2160 miles with the wind. The return trip takes 4 hours against the wind. Find the speed of the plane in still air and the speed of the wind.
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Algebra.Com's Answer #248651 by mananth(16946)![]() ![]() You can put this solution on YOUR website! time = distance /speed \n" ); document.write( "speed upwind = x-y \n" ); document.write( "speed downwind = x+y \n" ); document.write( "time = 2160/x+y=3 \n" ); document.write( "x+y = 2160/3 \n" ); document.write( "x+y=720........................1 \n" ); document.write( "upwind \n" ); document.write( "time = 2160/x-y = 4 \n" ); document.write( "2160/4 = x-y \n" ); document.write( "340 = x-y......................2 \n" ); document.write( "add equation 1 & 2 \n" ); document.write( "2x= 1060 \n" ); document.write( "x= 530 mph \n" ); document.write( "..... \n" ); document.write( "x+y=720 \n" ); document.write( "530+y=720 \n" ); document.write( "y=720-530 \n" ); document.write( "y= 90 mph \n" ); document.write( " \n" ); document.write( " |