document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=347735>Question 347735</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1)the length of a rectangular rug is 1 ft more than the width and a diagonal of the rug is 5 ft. Find the length and the width. 2) one leg of right triangle is 7 cm less than the length of the other leg. The length of the hypotenuse is 13 cm. Find the lengths of the legs </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248642 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248642\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1) L=W+1<BR>\n" );
document.write( "L^2+W^2=5^2<BR>\n" );
document.write( "(W+1)^2+W^2=25<BR>\n" );
document.write( "W^2+2W+1+W^2=25<BR>\n" );
document.write( "2W^2+2W+1-25=0<BR>\n" );
document.write( "2W^2+2W-24=0<BR>\n" );
document.write( "2(W^2+W-12)=0<BR>\n" );
document.write( "(W+4)(W-3)=0<BR>\n" );
document.write( "W-3=0<BR>\n" );
document.write( "W=3 ANS.<BR>\n" );
document.write( "L=3+1=4 ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "4^2+3^2=5^2<BR>\n" );
document.write( "16+9=25<BR>\n" );
document.write( "25=25<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );