document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=347307>Question 347307</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What would be the equation for, A friend calls you and asks you to meet at a location 3 miles from your home in 20 minutes. You set off on your bike after the telephone call. Write and solve an inequality to find out an average rate in miles per minute you could ride to be at your meeting place within 20 minutes? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248593 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248593\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> speed=(distance/time)\r<BR>\n" );
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document.write( "distance to be travelled=3miles\r<BR>\n" );
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document.write( "therefore....distance/speed is less than or equal to time\r<BR>\n" );
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document.write( "3/speed is less than or equal to 20mins\r<BR>\n" );
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document.write( "therefore cross multiply\r<BR>\n" );
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document.write( "speed greater than or equal to (3/20)miles per min<BR>\n" );
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