document.write( "Question 347721: 3[(2-3)^2 + (6 - 4)^2]\r
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document.write( "I have not done this in quite a while and was needing some assistance. Can you please take a look at it and qive me some help. Thank you very much. \n" );
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Algebra.Com's Answer #248584 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! 3[(2-3)^2 + (6 - 4)^2] ... Start with the given expression.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3[(-1)^2 + (2)^2] ... Subtract.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3[1 + 4] ... Square each term.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3[5] ... Add\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "15 ... Multiply\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So 3[(2-3)^2 + (6 - 4)^2] = 15\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Jim \n" ); document.write( " |