document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=347473>Question 347473</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A can do a piece of work in two-thirds as many day as B,and B can do it in three-fourths as many days as C. Working together, they can do it in 2 and ten-thirteenths days. In how many days can each of them alone do the work. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248557 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248557\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2 10/13 = 36/13\r<BR>\n" );
document.write( "\n" );
document.write( "C takes n days to do one job.<BR>\n" );
document.write( "B takes (3/4) n days to do one job.<BR>\n" );
document.write( "A takes (2/3) [(3/4) n] days to do one job. [= n/2 days to do one job.]\r<BR>\n" );
document.write( "\n" );
document.write( "C can complete 1/n jobs in a day.<BR>\n" );
document.write( "B can complete 4/(3n) jobs in a day.<BR>\n" );
document.write( "A can complete 2/n jobs in a day.\r<BR>\n" );
document.write( "\n" );
document.write( "36/13 days * [1/n jobs/day + 4/(3n) jobs/day + 2/n jobs/day] = 1 job.\r<BR>\n" );
document.write( "\n" );
document.write( "solve for n, then plug-n-chug into:\r<BR>\n" );
document.write( "\n" );
document.write( "C takes n days to do one job.<BR>\n" );
document.write( "B takes (3/4) n days to do one job.<BR>\n" );
document.write( "A takes n/2 days to do one job.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );