document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=347465>Question 347465</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man walks from one town to another in 5 hours. Had he walked of a kilometer faster, he would have reached his destination 36 minutes earlier. Find the distance between the two towns and the rate at which he walked. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248556 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248556\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the speed at which the man traveled be x\r<BR>\n" );
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document.write( "Let his speed had he walked a kilometres faster be y\r<BR>\n" );
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document.write( "y = x+1.............Equation(1)\r<BR>\n" );
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document.write( "5x = 4.4y...........Equation(2)\r<BR>\n" );
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document.write( "Sub y in (2),\r<BR>\n" );
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document.write( "5x=4.4(x+1)\r<BR>\n" );
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document.write( "5x=4.4x+4.4\r<BR>\n" );
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document.write( "0.6x=4.4\r<BR>\n" );
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document.write( "x=22/3 km/h\r<BR>\n" );
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document.write( "D=ST\r<BR>\n" );
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document.write( "D=5*22/3\r<BR>\n" );
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document.write( "D=110/3 km\r<BR>\n" );
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document.write( "Therefore, he walked at a rate of approximately 7.3 km/h and traveled a \r<BR>\n" );
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document.write( "distance of approximately 36.7 km<BR>\n" );
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