document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39227>Question 39227</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the foci of the graph. Then draw the graph.<BR>\n" );
document.write( "x^2/16 - y^2/36 = 1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24854 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24854\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X^2/16 - Y^2/36 =1\r<BR>\n" );
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document.write( "THE EQN. OF A HYPERBOLA.STD.EQN.IS.<BR>\n" );
document.write( "(X-H)^2/A^2 - (Y-K)^2/B^2=1..WHERE<BR>\n" );
document.write( "(H,K) IS CENTRE.....(0,0) HERE<BR>\n" );
document.write( "A=4 AND B=6<BR>\n" );
document.write( "ECCENTRICITY =E =SQRT[(A^2+B^2)/(A^2)]=SQRT[(16+36)/16]=SQRT(13)/2\r<BR>\n" );
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document.write( "A*E=4*SQRT(13)/2=2SQRT(13)<BR>\n" );
document.write( "FOCI ARE (H+-AE,K)......(+2SQRT(13),0)<BR>\n" );
document.write( "AND ......(-2SQRT(13),0)\r<BR>\n" );
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document.write( "GRAPH IS GIVEN BELOW..<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C%0D%0A%282.25%2A%28x%5E2-16%29%29%5E0.5%2C-%282.25%2A%28x%5E2-16%29%29%5E0.5%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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