document.write( "Question 347582: 1-the graduate selection committee wants to select the top 10% of applicants. On a standardized test with a mean of 500 and a standard diviation of 100, what would be the cutoff score for selecting the top 10% of applicants, assuming that test is normally distributed?
\n" ); document.write( "2- The average commute time via train from the chicago O'Hare Airport to downtown is 60 minutes with a s=15 minutes.Assume that the commute times are normally distributed. what proportion of communtes would be:
\n" ); document.write( "a. Longer than 80 minutes?
\n" ); document.write( "b. Less than 50 minutes?
\n" ); document.write( "c. Between 45 and 75 minutes?
\n" ); document.write( "3- Bob takes an online IQ test and finds out that his IQ according to the test is 134. Assuming that the mean IQ is 100, the s=15, and the distribution of IQ scoes is normal, what proportion of the population would score higher than Bob? Lower than Bob?
\n" ); document.write( "

Algebra.Com's Answer #248531 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
1-the graduate selection committee wants to select the top 10% of applicants. On a standardized test with a mean of 500 and a standard diviation of 100, what would be the cutoff score for selecting the top 10% of applicants, assuming that test is normally distributed?
\n" ); document.write( "----
\n" ); document.write( "Find the z-value with a right tail of 10%: invNorm(0.90) = 1.2816
\n" ); document.write( "---
\n" ); document.write( "Then use x = zs+u to find the raw score (x).
\n" ); document.write( "x = 1.2816*100+500 = 628.16
\n" ); document.write( "----------------------------------------
\n" ); document.write( "2- The average commute time via train from the chicago O'Hare Airport to downtown is 60 minutes with a s=15 minutes.Assume that the commute times are normally distributed. what proportion of commutes would be:
\n" ); document.write( "a. Longer than 80 minutes?
\n" ); document.write( "z(80) = (80-60)/15 = 4/3
\n" ); document.write( "P(x> 80) = P(z> 4/3) = normalcdf(4/3,100) = 0.0912
\n" ); document.write( "---------------------------------------------------------
\n" ); document.write( "b. Less than 50 minutes?
\n" ); document.write( "z(50) = (50-60)/15 = -2/3
\n" ); document.write( "P(x< 50) = P(z< -2/3) = normalcdf(-100,-2/3) = 0.2525
\n" ); document.write( "----------------------------------------
\n" ); document.write( "c. Between 45 and 75 minutes?
\n" ); document.write( "Same procedure.
\n" ); document.write( "Can you do that?
\n" ); document.write( "----------------------
\n" ); document.write( "---------------------
\n" ); document.write( "3- Bob takes an online IQ test and finds out that his IQ according to the test is 134. Assuming that the mean IQ is 100, the s=15, and the distribution of IQ scoes is normal, what proportion of the population would score higher than Bob? Lower than Bob?
\n" ); document.write( "---
\n" ); document.write( "Find z-score of 134 = N.
\n" ); document.write( "Find P(z >N)
\n" ); document.write( "Find P(z < N)
\n" ); document.write( "Can you do that?
\n" ); document.write( "======================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" ); document.write( "
\n" );