document.write( "Question 347599: How many liters of a 60% acid solution must be mixed with a 75% acid solution to get 20 liters of a 72% solution? \n" ); document.write( "
Algebra.Com's Answer #248468 by Fombitz(32388)\"\" \"About 
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Let A be the amount of 60% acid solution.
\n" ); document.write( "Let B be the amount of 75% acid solution.
\n" ); document.write( "Volume equation:
\n" ); document.write( "1.\"A%2BB=20\"
\n" ); document.write( "Concentration equation:
\n" ); document.write( "\"60A%2B75B=72%2820%29\"
\n" ); document.write( "2.\"4A%2B5B=96\"
\n" ); document.write( "From eq. 1,
\n" ); document.write( "\"A=20-B\"
\n" ); document.write( "Substitute into eq. 2,
\n" ); document.write( "\"4%2820-B%29%2B5B=96\"
\n" ); document.write( "\"80-4B%2B5B=96\"
\n" ); document.write( "\"highlight%28B=16%29\"liters
\n" ); document.write( "Then from eq. 1,
\n" ); document.write( "\"A%2B16=20\"
\n" ); document.write( "\"highlight%28A=4%29\"liters
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