document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=347566>Question 347566</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could you please help me solve 2y^3-11y^2+12y=0?\r<BR>\n" );
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document.write( "I'm completely blank and very tired and can't think anymore (had a volleyball game today after school and am trying to do loads of homework tonight).\r<BR>\n" );
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document.write( "Here's what I tried:\r<BR>\n" );
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document.write( "2(y.y.y)-11(y.y)+12y=0<BR>\n" );
document.write( "2(y)-11+12y=0<BR>\n" );
document.write( "-11+14y=0\r<BR>\n" );
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document.write( "+11   =   +11\r<BR>\n" );
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document.write( "14y=11<BR>\n" );
document.write( "___   ____<BR>\n" );
document.write( "14     14\r<BR>\n" );
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document.write( "y=11/14\r<BR>\n" );
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document.write( "Thank you so much for your time and help.\r<BR>\n" );
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document.write( "Darlyn </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248463 by </B><A HREF=/tutors/aboutme.mpl?userid=haileytucki><B>haileytucki(390)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=haileytucki><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=haileytucki><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248463\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2y^(3)-11y^(2)+12y=0\r<BR>\n" );
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document.write( "Factor out the GCF of y from each term in the polynomial.<BR>\n" );
document.write( "y(2y^(2))+y(-11y)+y(12)=0\r<BR>\n" );
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document.write( "Factor out the GCF of y from 2y^(3)-11y^(2)+12y.<BR>\n" );
document.write( "y(2y^(2)-11y+12)=0\r<BR>\n" );
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document.write( "In this problem -(3)/(2)*-4=12 and -(3)/(2)-4=-11, so insert -(3)/(2) as the right hand term of one factor and -4 as the right-hand term of the other factor.<BR>\n" );
document.write( "y(y-(3)/(2))(y-4)=0\r<BR>\n" );
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document.write( "Remove the fraction by multiplying the first term of the factor by the denominator of the second term.<BR>\n" );
document.write( "y(2y-3)(y-4)=0\r<BR>\n" );
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document.write( "Set the single term factor on the left-hand side of the equation equal to 0.<BR>\n" );
document.write( "y=0\r<BR>\n" );
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document.write( "Set each of the factors of the left-hand side of the equation equal to 0.<BR>\n" );
document.write( "2y-3=0_y-4=0\r<BR>\n" );
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document.write( "Since -3 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 3 to both sides.<BR>\n" );
document.write( "2y=3_y-4=0\r<BR>\n" );
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document.write( "Divide each term in the equation by 2.<BR>\n" );
document.write( "(2y)/(2)=(3)/(2)_y-4=0\r<BR>\n" );
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document.write( "Simplify the left-hand side of the equation by canceling the common factors.<BR>\n" );
document.write( "y=(3)/(2)_y-4=0\r<BR>\n" );
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document.write( "Set each of the factors of the left-hand side of the equation equal to 0.<BR>\n" );
document.write( "y=(3)/(2)_y-4=0\r<BR>\n" );
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document.write( "Since -4 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 4 to both sides.<BR>\n" );
document.write( "y=(3)/(2)_y=4\r<BR>\n" );
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document.write( "The complete solution is the set of the individual solutions.<BR>\n" );
document.write( "y=0,(3)/(2),4 </SPAN>\n" );
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