document.write( "Question 347536: A rectangular field with area 5000 meters squared is enclosed by 300 meters of fencing. Find the dimensions of the field. \n" ); document.write( "
Algebra.Com's Answer #248455 by unlockmath(1688)\"\" \"About 
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Hello,
\n" ); document.write( "Let's have L represent Length and W be width. We can set up 2 equations as:
\n" ); document.write( "LxW=5000
\n" ); document.write( "2L+2W=300
\n" ); document.write( "Now work with the 2nd equation and subtract 2W and divide by 2 to get:
\n" ); document.write( "L=-W+150
\n" ); document.write( "Plug this into the first equation:
\n" ); document.write( "W(-W+150)=5000
\n" ); document.write( "Subtract 5000 from both sides:
\n" ); document.write( "-W^2+150w-5000=0
\n" ); document.write( "This could also be written as:
\n" ); document.write( "W^2-150W+5000=0
\n" ); document.write( "Factored as:
\n" ); document.write( "(W-50)(W-100)=0
\n" ); document.write( "Solve W
\n" ); document.write( "W=50
\n" ); document.write( "W=100
\n" ); document.write( "So we can have 2 different solutions.
\n" ); document.write( "Width can be 50 meters and length 100 meters
\n" ); document.write( "or Width can be 100 meters and length 50 meters.
\n" ); document.write( "Make sense?
\n" ); document.write( "RJ
\n" ); document.write( "www.math-unlock.com \n" ); document.write( "
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