document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=347531>Question 347531</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve by completing the square\r<BR>\n" );
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document.write( "x^2-2x-5=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248445 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248445\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay from<BR>\n" );
document.write( "x^2 - 2x - 5 = 0<BR>\n" );
document.write( "we group our terms like this<BR>\n" );
document.write( "(x^2 - 2x + something) - 5 = 0 + something<BR>\n" );
document.write( "The \"something\" is always half of the middle term's coefficient squared...here it is 1.<BR>\n" );
document.write( "so we have<BR>\n" );
document.write( "(x^2 - 2x + 1) - 5 = 0 + 1<BR>\n" );
document.write( "(x - 1)^2 - 5 = 1<BR>\n" );
document.write( "(x - 1)^2 = 6<BR>\n" );
document.write( "take square root of both sides now<BR>\n" );
document.write( "x - 1 = +/- sqrt(6)<BR>\n" );
document.write( "x = 1 +/- sqrt(6) </SPAN>\n" );
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