document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=347496>Question 347496</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The frame of a picture is 28 cm by 32 cm outside and is of uniform width. What is the width of the frame if 192 cm^2 of the picture shows? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248443 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248443\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the width of the frame be x.<BR>\n" );
document.write( "Thus the width of the picture alone is 28 - 2x and the height would be 32 - 2x (notice x width on either side)...<BR>\n" );
document.write( "So we set up<BR>\n" );
document.write( "(28 - 2x)(32 - 2x) = 192 and solve for x, the width of the frame...<BR>\n" );
document.write( "896 - 56x - 64x + 4x^2 = 192<BR>\n" );
document.write( "4x^2 - 120x + 704 = 0<BR>\n" );
document.write( "x^2 - 30x + 176 = 0<BR>\n" );
document.write( "(x - 8)(x - 22) = 0<BR>\n" );
document.write( "x = 8 or x = 22<BR>\n" );
document.write( "but it can't be 22, so<BR>\n" );
document.write( "x = 8 cm </SPAN>\n" );
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