document.write( "Question 39396: Vern invested $11,000. Part was invested at 15% and part at 13%. If the total interest at the end of the year is $1,610, how much did he invest at 15%?\r
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document.write( "2 pts \n" );
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Algebra.Com's Answer #24843 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! Let x be the amount invested at 15%. \n" ); document.write( "Then 11000 - x is the amount invested at 13%. \n" ); document.write( "So we have the equation \n" ); document.write( "(.15)x + (.13)(11000 - x) = 1610 \n" ); document.write( "Multiply all by 100 to clear decimals (makes it easier) \n" ); document.write( "15x + 13(11000 - x) = 161000 \n" ); document.write( "15x + 143000 - 13x = 161000 \n" ); document.write( "2x = 18000 \n" ); document.write( "x = $9000, the amount at 15% \n" ); document.write( "11000 - x = $2000, the amount at 13% \n" ); document.write( " |