document.write( "Question 39396: Vern invested $11,000. Part was invested at 15% and part at 13%. If the total interest at the end of the year is $1,610, how much did he invest at 15%?\r
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Algebra.Com's Answer #24843 by fractalier(6550)\"\" \"About 
You can put this solution on YOUR website!
Let x be the amount invested at 15%.
\n" ); document.write( "Then 11000 - x is the amount invested at 13%.
\n" ); document.write( "So we have the equation
\n" ); document.write( "(.15)x + (.13)(11000 - x) = 1610
\n" ); document.write( "Multiply all by 100 to clear decimals (makes it easier)
\n" ); document.write( "15x + 13(11000 - x) = 161000
\n" ); document.write( "15x + 143000 - 13x = 161000
\n" ); document.write( "2x = 18000
\n" ); document.write( "x = $9000, the amount at 15%
\n" ); document.write( "11000 - x = $2000, the amount at 13%
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