document.write( "Question 347483: a car radiator containes 10 liters of a 30% antifreeze solution. how many liters will have to be replaced with pure antifreeze if the resulting solution is to be 50% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #248424 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! a car radiator contains 10 liters of a 30% antifreeze solution. \n" ); document.write( "how many liters will have to be replaced with pure antifreeze if the resulting solution is to be 50% antifreeze? \n" ); document.write( "----- \n" ); document.write( "Equation: \n" ); document.write( "active - active + active = active \n" ); document.write( "--- \n" ); document.write( "0.30*10 - 0.30x + 1.00x = 0.50*10 liters \n" ); document.write( "----------------------------------- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "30*10 - 30x + 100x = 50*10 \n" ); document.write( "70x = 20*10 \n" ); document.write( "x = 200/70 = 2.8571 liters (amt. to replaced by pure antifreeze) \n" ); document.write( "============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============================== \n" ); document.write( " \n" ); document.write( " |