document.write( "Question 347387: an alloy of metals is 25% copper. another alloy is 50% copper. how much of each should be used to make 1000 grams of an alloy that is 45% copper? \n" ); document.write( "

Algebra.Com's Answer #248416 by josmiceli(19441) $\"\"$ $\"About$

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given:
\n" ); document.write( " $\".25a+%2B+.5b+=+.45%2A1000\"$
\n" ); document.write( " $\"25a+%2B+50b+=+45000%0D%0A%7B%7B%7Ba+%2B+b+=+1000\"$
\n" ); document.write( " $\"25a+%2B+25b+=+25000\"$
\n" ); document.write( "By subtraction:
\n" ); document.write( " $\"25b+=+20000\"$
\n" ); document.write( " $\"b+=+800\"$
\n" ); document.write( " $\"a+=+1000+-+800\"$
\n" ); document.write( " $\"a+=+200\"$
\n" ); document.write( "200 grams of the 25% copper and 800 grams
\n" ); document.write( "of the 50% copper should be used \n" ); document.write( "

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