document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=347408>Question 347408</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of an odd integer and 3/4 the next odd integer, and two times the following odd integer.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248413 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248413\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If we let the first integer be x, then the next odd one is x + 2, and the next would be x + 4...so the statement is translated as<BR>\n" );
document.write( "x + (3/4)(x + 2) + 2(x + 4)<BR>\n" );
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