document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=347404>Question 347404</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one of two complementary angles is 35 degrees larger than the other . What is the measure of both angles ?<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248400 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248400\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since the two angles are complementary, they add up to 90...<BR>\n" );
document.write( "If we call the first one x, then the other must be 90-x...<BR>\n" );
document.write( "Since they are 35 different, we write<BR>\n" );
document.write( "x = (90 - x) + 35<BR>\n" );
document.write( "now solve, and get<BR>\n" );
document.write( "x = 90 - x + 35<BR>\n" );
document.write( "x = -x + 125<BR>\n" );
document.write( "2x = 125<BR>\n" );
document.write( "x = 62.5 deg<BR>\n" );
document.write( "the other must be<BR>\n" );
document.write( "90 - 62.5 = 27.5 deg </SPAN>\n" );
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