document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=347427>Question 347427</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you factor 2X^3 minus 5X minus 3? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248396 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248396\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well, by looking at it, I can see that x = -1 is a root, so (x+1) is a factor...<BR>\n" );
document.write( "If you divide it by x+1 you get,<BR>\n" );
document.write( "2x^2 - 2x - 3<BR>\n" );
document.write( "wich isn't directly factorable...you'd use the quadratic here...<BR>\n" );
document.write( "so that x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2B-+%281%2Bsqrt%287%29%29%2F2 ALIGN=MIDDLE  ALT=\"%2B-+%281%2Bsqrt%287%29%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "and the answer factored appears to be<BR>\n" );
document.write( "(x + 1)(x + (1+sqrt(7)/2)(x - (1+sqrt(7)/2) </SPAN>\n" );
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