document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=347413>Question 347413</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cyclists, 108 miles apart, start riding toward each other at the same time. One cycles 3 times as fast as the other. If they meet 3 hours later, what is the speed (in mi/h) of the faster cyclist?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248395 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248395\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the speed of 1 be x mph<BR>\n" );
document.write( "the other willl be 3x<BR>\n" );
document.write( "....<BR>\n" );
document.write( "Time = distance / speed<BR>\n" );
document.write( "cyclist 1 time = 108/x<BR>\n" );
document.write( "cyclist 2  time =108/3x<BR>\n" );
document.write( ".....<BR>\n" );
document.write( "108/x + 108/3x = 3<BR>\n" );
document.write( "324+108 / 3x= 3<BR>\n" );
document.write( "432/3x=3<BR>\n" );
document.write( "432=9x<BR>\n" );
document.write( "x= 432/9<BR>\n" );
document.write( "x=48 mph<BR>\n" );
document.write( "faster cyclist = 3*48 = 144 mph </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );