document.write( "Question 347411: Paul is 3 times as old as anna, in 12 years , he will be twice as old as anna . What is pauls age? \n" ); document.write( "
Algebra.Com's Answer #248387 by fractalier(6550)\"\" \"About 
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Always set the variables in age problems NOW.
\n" ); document.write( "Thus let P be Paul's age NOW, and A be Anna's NOW.
\n" ); document.write( "Thus
\n" ); document.write( "P = 3A
\n" ); document.write( "In 12 years,
\n" ); document.write( "P + 12 = 2(A + 12)
\n" ); document.write( "now substitute in for P and get
\n" ); document.write( "3A + 12 = 2(A + 12)
\n" ); document.write( "3A + 12 = 2A + 24
\n" ); document.write( "A + 12 = 24
\n" ); document.write( "A = 12
\n" ); document.write( "Then, back-substitute and get
\n" ); document.write( "P = 36
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