document.write( "Question 347411: Paul is 3 times as old as anna, in 12 years , he will be twice as old as anna . What is pauls age? \n" ); document.write( "
Algebra.Com's Answer #248387 by fractalier(6550) You can put this solution on YOUR website! Always set the variables in age problems NOW. \n" ); document.write( "Thus let P be Paul's age NOW, and A be Anna's NOW. \n" ); document.write( "Thus \n" ); document.write( "P = 3A \n" ); document.write( "In 12 years, \n" ); document.write( "P + 12 = 2(A + 12) \n" ); document.write( "now substitute in for P and get \n" ); document.write( "3A + 12 = 2(A + 12) \n" ); document.write( "3A + 12 = 2A + 24 \n" ); document.write( "A + 12 = 24 \n" ); document.write( "A = 12 \n" ); document.write( "Then, back-substitute and get \n" ); document.write( "P = 36 \n" ); document.write( " |