document.write( "Question 347343: The sum of three numbers is 107. The second number is 7 more than the first number and the third number is 6 less than twice the second number. Find the numbers. \n" ); document.write( "
Algebra.Com's Answer #248377 by rfer(16322)![]() ![]() ![]() You can put this solution on YOUR website! x+x+7+2(x+7)-6=107 \n" ); document.write( "4x+21-6=107 \n" ); document.write( "4x=92 \n" ); document.write( "x=23 \n" ); document.write( "x+7=30 \n" ); document.write( "2(x+7)-6=54 \n" ); document.write( " |