document.write( "Question 347300: a chemist needs to mix 20L of a 40% acid solution with some 70% acid solution to obtain a mixture that is 50% acid. How many liters of the 70% acid solution should be used? \n" ); document.write( "
Algebra.Com's Answer #248364 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .70x+.40*20=.50(20+x) \n" ); document.write( ".70x+8=10+.50x \n" ); document.write( ".70x-.50x=10-8 \n" ); document.write( ".20x=2 \n" ); document.write( "x=2/.2 \n" ); document.write( "x=10 L of 70% acid is used. \n" ); document.write( "Proof: \n" ); document.write( ".70*10+.40*.2=.50(20=10) \n" ); document.write( "7+8=.5*30 \n" ); document.write( "15=15 \n" ); document.write( " \n" ); document.write( " |