document.write( "Question 347300: a chemist needs to mix 20L of a 40% acid solution with some 70% acid solution to obtain a mixture that is 50% acid. How many liters of the 70% acid solution should be used? \n" ); document.write( "
Algebra.Com's Answer #248364 by checkley77(12844)\"\" \"About 
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.70x+.40*20=.50(20+x)
\n" ); document.write( ".70x+8=10+.50x
\n" ); document.write( ".70x-.50x=10-8
\n" ); document.write( ".20x=2
\n" ); document.write( "x=2/.2
\n" ); document.write( "x=10 L of 70% acid is used.
\n" ); document.write( "Proof:
\n" ); document.write( ".70*10+.40*.2=.50(20=10)
\n" ); document.write( "7+8=.5*30
\n" ); document.write( "15=15
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