document.write( "Question 347266: I am terrible at fractions and I am totally lost with using the addition method with fractions. Please help\r
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document.write( "3/7x+5/9y=27
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document.write( "1/9x+2/7y=7\r
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document.write( "These are fractions \n" );
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Algebra.Com's Answer #248330 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 3/7x+5/9y=27 multiply by 1/9 \n" ); document.write( "1/9x+2/7y=7 multiply by -3/7 & add. \n" ); document.write( "1/9*3/7x+1/9*5/9y=1/9*27 \n" ); document.write( "3/63x+5/81y=3 \n" ); document.write( "-3/7*1/9x-3/7*2/7y=-3/7*7 \n" ); document.write( "-3/63x-6/49y=-3 \n" ); document.write( "3/63x+5/81y=3 \n" ); document.write( "----------------------------- \n" ); document.write( "-6/81y+5/49y=0 \n" ); document.write( "y(-6/81+5/49)=0 \n" ); document.write( "y=0 ans \n" ); document.write( "3/7x=27 \n" ); document.write( "3x/7=27 \n" ); document.write( "3x=7*27 \n" ); document.write( "3x=189 \n" ); document.write( "x=189/3 \n" ); document.write( "x=63 ans. \n" ); document.write( "Proof: \n" ); document.write( "1/9*63+2/7*0=7 \n" ); document.write( "63/9=7 \n" ); document.write( "7=7 \n" ); document.write( " \n" ); document.write( " |