document.write( "Question 347266: I am terrible at fractions and I am totally lost with using the addition method with fractions. Please help\r
\n" ); document.write( "\n" ); document.write( "3/7x+5/9y=27
\n" ); document.write( "1/9x+2/7y=7\r
\n" ); document.write( "\n" ); document.write( "These are fractions
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Algebra.Com's Answer #248330 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
3/7x+5/9y=27 multiply by 1/9
\n" ); document.write( "1/9x+2/7y=7 multiply by -3/7 & add.
\n" ); document.write( "1/9*3/7x+1/9*5/9y=1/9*27
\n" ); document.write( "3/63x+5/81y=3
\n" ); document.write( "-3/7*1/9x-3/7*2/7y=-3/7*7
\n" ); document.write( "-3/63x-6/49y=-3
\n" ); document.write( "3/63x+5/81y=3
\n" ); document.write( "-----------------------------
\n" ); document.write( "-6/81y+5/49y=0
\n" ); document.write( "y(-6/81+5/49)=0
\n" ); document.write( "y=0 ans
\n" ); document.write( "3/7x=27
\n" ); document.write( "3x/7=27
\n" ); document.write( "3x=7*27
\n" ); document.write( "3x=189
\n" ); document.write( "x=189/3
\n" ); document.write( "x=63 ans.
\n" ); document.write( "Proof:
\n" ); document.write( "1/9*63+2/7*0=7
\n" ); document.write( "63/9=7
\n" ); document.write( "7=7
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