document.write( "Question 39398: I am a beginner.\r
\n" ); document.write( "\n" ); document.write( "I am stuck on correct answer for:\r
\n" ); document.write( "\n" ); document.write( "IF x - two-sevenths(2 over 7)x = 5, then x = \r
\n" ); document.write( "\n" ); document.write( "I am not using a specific book. I am just practicing..........
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Algebra.Com's Answer #24833 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"%282%2F7%29x+=+5\"
\n" ); document.write( "there are several ways you could have written the left side of
\n" ); document.write( "this equation, and their all equal to eachother.
\n" ); document.write( "\"%282x%29%2F7+=+5\"
\n" ); document.write( "\"2%2A%28x%2F7%29+=+5\"
\n" ); document.write( "\"%28x%2F7%29%2A2+=+5\"
\n" ); document.write( "\"%282%2F7%29x+=+5\"
\n" ); document.write( "notice that the 7 stays below the fraction line in each case
\n" ); document.write( "and all I'm doing is changing the order of x and 2.
\n" ); document.write( "To solve any equation, just do the same thing to both sides
\n" ); document.write( "at each step. The \"=\" sign is the balence point and you're keeping
\n" ); document.write( "both sides balenced.
\n" ); document.write( "multiply both sides by 7
\n" ); document.write( "\"7%2A%282%2F7%29x+=+7%2A5\"
\n" ); document.write( "you can rewrite the left side as follows
\n" ); document.write( "\"%287%2F7%29%2A2x+=+7%2A5\"
\n" ); document.write( "7/7 = 1 (anything divided by itself is 1.
\n" ); document.write( "1*(2x) is the same as 2x
\n" ); document.write( "\"2x+=+7%2A5\"
\n" ); document.write( "multiply out the right side
\n" ); document.write( "\"2x+=+35\"
\n" ); document.write( "divide both sides by 2
\n" ); document.write( "\"%282%2F2%29x+=+35%2F2\"
\n" ); document.write( "2/2 is 1 and 1*x is the same as x.
\n" ); document.write( "\"x+=+35%2F2\" is the answer (or 17 1/2 if you like)
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